Sample Questions

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Exam Questions

Question 1
What is the value of 2/5 multiplied by ¾ divide by 8/5
A. 12\25
B. 1\3
C. 3\16
D. 64/75
Correct Answer: C
Rationale: To solve (2/5) * (3/4)÷ (8/5), first multiply the fractions: (2/5) * (3/4) = (2*3)/(5*4) = 6/20 = 3/10. Then, divide by 8/5, which is equivalent to multiplying by 5/8: (3/10) * (5/8) = (3*5)/(10*8) = 15/80 = 3/16. Thus, the correct answer is 3/16.
Question 2
Simplify 6^2 - 3^2
A. 6
B. 9
C. 27
D. 3
Correct Answer: C
Rationale: Calculate 6^2 = 36 and 3^2 = 9. Then, subtract: 36 - 9 = 27. Thus, the correct answer is 27.
Question 3
2^3 * 27^(1/3) * 1^3
A. 54
B. 24
C. 72
D. 18
Correct Answer: B
Rationale: First, compute each term: 2^3 = 8, 27^(1/3) is the cube root of 27, which is 3 (since 3^3 = 27), and 1^3 = 1. Then, multiply: 8 * 3 * 1 = 24. Thus, the correct answer is 24.
Question 4
((5^3 * 2^4)^2)(5^(-2) * 2^5)
A. 5^3 * 2^11
B. 5^(-12) * 2^40
C. 5^4 * 2^13
D. (-5)^8 * 2^13
Correct Answer: C
Rationale: First, simplify inside the parentheses: (5^3 * 2^4)^2 = (5^3)^2 * (2^4)^2 = 5^6 * 2^8. Then, multiply by 5^(-2) * 2^5: (5^6 * 2^8) * (5^(-2) * 2^5) = 5^(6-2) * 2^(8+5) = 5^4 * 2^13. The negative in option D is incorrect as all bases are positive. Thus, the correct answer is 5^4 * 2^13.
Question 5
The mass of an amoeba is approximately 4.0 × 10^(-6) grams. Approximately how many amoebas are present in a sample that weighs 1 gram?
A. 2.5 × 10^5
B. 4.0 × 10^7
C. 4.0 × 10^5
D. 2.5 × 10^7
Correct Answer: A
Rationale: To find the number of amoebas, divide the total mass (1 gram) by the mass of one amoeba (4.0 × 10^(-6) grams): 1÷ (4.0 × 10^(-6)) = 1 * (10^6 / 4.0) = 10^6 / 4 = 0.25 × 10^6 = 2.5 × 10^5. Thus, the correct answer is 2.5 × 10^5.